4q^2-9q+1=0

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Solution for 4q^2-9q+1=0 equation: 



4q^2-9q+1=0

a = 4; b = -9; c = +1;
Δ = b2-4ac
Δ = -92-4·4·1
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{65}}{2*4}=\frac{9-\sqrt{65}}{8}
$


$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{65}}{2*4}=\frac{9+\sqrt{65}}{8}
$

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